LeetCode Climbing Stairs
來源:程序員人生 發(fā)布時間:2014-12-07 09:38:42 閱讀次數(shù):2465次
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
思路分析:考察DP,定義ClimbWays數(shù)組,ClimbWays[n]表示n steps不同的走法,如果第n步是1個單步,這類情況的走法有ClimbWays[n⑴]種;如果第n步是1個雙步,這類情況的走法有ClimbWays[n⑵]種;因此可以得到DP方程ClimbWays[n]=ClimbWays[n⑴] + ClimbWays[n⑵] .
public class Solution {
public int climbStairs(int n) {
//04:10
int [] climbWays = new int[n+1];
if(n == 0) return 0;
if(n == 1) return 1;
climbWays[1] = 1;
climbWays[2] = 2;
for(int i = 3; i <= n; i++){
climbWays[i] = climbWays[i⑴] + climbWays[i⑵];
}
return climbWays[n];
}
//04:14
}
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