where 1=-1 and 1=1 會不會影響查詢效率?
來源:程序員人生 發布時間:2015-08-20 08:37:45 閱讀次數:4493次
今天用sql profiler跟1個底層生成的SQL 的時候,跟到這樣1段代碼:
WITH TempQuery AS
(
SELECT *, ROW_NUMBER() OVER (ORDER BY CreateTime DESC) AS 'RowNumberForSplit'
FROM (select E.Name as Name, U.RealyName as RealyName,C.[Description] as Descriptions,'求職者' as tsf ,C.Result,C.CreateTime from [Mr].[User_Complaint] UC inner join [Mr].[User] U on UC.UserCode=U.Code inner join [Mr].[Complaint] C on UC.ComplaintCode=C.Code inner join [Mr].[Enterprise] E on UC.EnterpriseCode=E.Code union select E.Name as Name, U.RealyName as RealyName,C.[Description] as Descriptions,'企業' as tsf ,C.Result,C.CreateTime from [Mr].[Enterprise_Complaint] EC inner join [Mr].[Enterprise] E on EC.EnterpriseCode=E.Code inner join [Mr].[Complaint] C on EC.ComplaintCode =C.Code inner join [Mr].[User] U on EC.UserCode=U.Code) CP
WHERE 1 = 1 AND 1=1
)
SELECT *
FROM TempQuery
WHERE RowNumberForSplit BETWEEN 1 AND 10;
SELECT COUNT(1) AS TOTAL_COUNT FROM (select E.Name as Name, U.RealyName as RealyName,C.[Description] as Descriptions,'求職者' as tsf ,C.Result,C.CreateTime from [Mr].[User_Complaint] UC inner join [Mr].[User] U on UC.UserCode=U.Code inner join [Mr].[Complaint] C on UC.ComplaintCode=C.Code inner join [Mr].[Enterprise] E on UC.EnterpriseCode=E.Code union select E.Name as Name, U.RealyName as RealyName,C.[Description] as Descriptions,'企業' as tsf ,C.Result,C.CreateTime from [Mr].[Enterprise_Complaint] EC inner join [Mr].[Enterprise] E on EC.EnterpriseCode=E.Code inner join [Mr].[Complaint] C on EC.ComplaintCode =C.Code inner join [Mr].[User] U on EC.UserCode=U.Code) CP WHERE 1 = 1 AND 1=1
然后你就看到后面隨著的where 1=1 and 1=1,之前也用過這個東西拼過條件,但是后來有人說這樣影響查詢性能,再后來又有人說不影響。然后我就迷茫了。。。
還是自己做個實驗測試下吧。
首先,先看1下沒有這個條件的查詢:
/****** Script for SelectTopNRows command from SSMS ******/
SELECT TOP 100000 [RESOURCE_ID]
,[CLASS]
,[SORT_ID]
,[XML_CONTENT]
,[SEARCH_CONTENT]
,[ROW_ID]
FROM [MCS_WORKFLOW].[WF].[GENERIC_FORM_RELATIVE_DATA] WHERE 1=1 AND 1=1
然后使用履行計劃來估計下:

然后加入條件:

在履行計劃中可以看到,開消幾近全部在聚集索引表的掃描上,對照上圖,發現這兩張表數據1致。

嘿嘿,看來他們的查詢效力是1樣的。
but why????百度下吧。。。。
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