您當前位置：首頁 > php開源 > php教程 > PHPMailer使用Gmail來發送郵件的連接smtp服務器錯誤

PHPMailer使用Gmail來發送郵件的連接smtp服務器錯誤

來源：程序員人生發布時間：2013-11-22 01:14:13 閱讀次數：4817次

我們在使用PHPMailer使用Gmail來發送郵件的連接smtp服務器錯誤提示:smtp error could not connect to smtp host ！了,這個是因為extension=php_openssl.dll未開啟導致的哦。

使用的PHPMailer版本:5.2.1,以下是PHPMailer的example文件夾里給出的:test_gamil_basic.php的部分代碼,代碼如下:

$mail = new PHPMailer();
$body = file_get_contents('contents.html'); //$body = $_POST['body'];
$body = eregi_replace("[]",'',$body);
$mail->IsSMTP(); // telling the class to use SMTP
$mail->SMTPDebug = 2; // enables SMTP debug information (for testing)
// 1 = errors and messages
// 2 = messages only
$mail->SMTPAuth = true; // enable SMTP authentication
$mail->SMTPSecure = "ssl"; // sets the prefix to the servier
$mail->Host = "smtp.gmail.com"; // sets GMAIL as the SMTP server or ssl://smtp.gmail.com
$mail->Port = 465; // set the SMTP port for the GMAIL server
$mail->Username = "yourusername@gmail.com"; // GMAIL username
$mail->Password = "yourpassword"; // GMAIL password
$mail->SetFrom('name@yourdomain.com', 'First Last');
$mail->AddReplyTo("name@yourdomain.com","First Last");
$mail->Subject = "PHPMailer Test Subject via smtp (Gmail), basic";
$mail->AltBody = "To view the message, please use an HTML compatible email viewer!"; // optional, comment out and test
$mail->MsgHTML($body);
$address = "whoto@otherdomain.com";
$mail->AddAddress($address, "John Doe");
$mail->AddAttachment("images/phpmailer.gif"); // attachment
$mail->AddAttachment("images/phpmailer_mini.gif"); // attachment
if(!$mail->Send()) {
echo "Mailer Error: " . $mail->ErrorInfo;
} else {
echo "Message sent!";
}